F(x)=-16x^2+32x+5

Solution for F(x)=-16x^2+32x+5 equation:

(F)=-16F^2+32F+5

We move all terms to the left:

(F)-(-16F^2+32F+5)=0

We get rid of parentheses

16F^2-32F+F-5=0

We add all the numbers together, and all the variables

16F^2-31F-5=0

a = 16; b = -31; c = -5;
Δ = b2-4ac
Δ = -312-4·16·(-5)
Δ = 1281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{1281}}{2*16}=\frac{31-\sqrt{1281}}{32}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{1281}}{2*16}=\frac{31+\sqrt{1281}}{32}
$